171 判断t1树是否包含t2树全部的拓扑结构
Table of Contents

ac

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.*;

class TreeNode{
    TreeNode left;
    TreeNode right;
    int val;

    public TreeNode(int val) {
        this.val = val;
        left = null;
        right = null;
    }
}

public class Main {
    public static Scanner sc = new Scanner(System.in);

    public static BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));

    public static long mod = (long) Math.pow(2, 29);

    public static void main(String[] args) throws Exception {
        String line;
        String[] strArr;
        line = reader.readLine();
        strArr = line.split(" ");
        int n = Integer.valueOf(strArr[0]);
        int rootVal = Integer.valueOf(strArr[1]);
        Map<Integer, TreeNode> mp = new HashMap<>(n);
        for (int i = 0; i < n; i++) {
            line = reader.readLine();
            strArr = line.split(" ");
            int val = Integer.valueOf(strArr[0]);
            int leftVal = Integer.valueOf(strArr[1]);
            int rightVal = Integer.valueOf(strArr[2]);

            if (!mp.containsKey(val)) {
                mp.put(val, new TreeNode(val));
            }
            if (leftVal != 0) {
                if (!mp.containsKey(leftVal)) {
                    mp.put(leftVal, new TreeNode(leftVal));
                }
                mp.get(val).left = mp.get(leftVal);
            }
            if (rightVal != 0) {
                if (!mp.containsKey(rightVal)) {
                    mp.put(rightVal, new TreeNode(rightVal));
                }
                mp.get(val).right = mp.get(rightVal);
            }
        }
        TreeNode root = mp.get(rootVal);

        mp.clear();
        line = reader.readLine();
        strArr = line.split(" ");
        n = Integer.valueOf(strArr[0]);
        rootVal = Integer.valueOf(strArr[1]);
        for (int i = 0; i < n; i++) {
            line = reader.readLine();
            strArr = line.split(" ");
            int val = Integer.valueOf(strArr[0]);
            int leftVal = Integer.valueOf(strArr[1]);
            int rightVal = Integer.valueOf(strArr[2]);

            if (!mp.containsKey(val)) {
                mp.put(val, new TreeNode(val));
            }
            if (leftVal != 0) {
                if (!mp.containsKey(leftVal)) {
                    mp.put(leftVal, new TreeNode(leftVal));
                }
                mp.get(val).left = mp.get(leftVal);
            }
            if (rightVal != 0) {
                if (!mp.containsKey(rightVal)) {
                    mp.put(rightVal, new TreeNode(rightVal));
                }
                mp.get(val).right = mp.get(rightVal);
            }
        }

        TreeNode subRoot = mp.get(rootVal);

        boolean b = isInclude(root, subRoot);
        System.out.println(b ? "true": "false");
    }

    static boolean isInclude(TreeNode root, TreeNode subRoot){
        if(root == null){
            return false;
        }
        return contains(root, subRoot) || isInclude(root.left, subRoot) || isInclude(root.right, subRoot);
    }

    static boolean contains(TreeNode root1, TreeNode root2){
        if(root1 == null && root2 != null){
            return false;
        }
        // root2 为null root1随意 都是匹配的
        if(root1 != null && root2 == null){
            return true;
        }
        if(root1 == null && root2 == null){
            return true;
        }
        if(root1.val != root2.val){
            return false;
        }
        return contains(root1.left, root2.left) && contains(root1.right, root2.right);
    }

}
/*
10 1
1 2 3
2 4 5
4 8 9
8 0 0
9 0 0
5 10 0
10 0 0
3 6 7
6 0 0
7 0 0
4 2
2 4 5
5 0 0
4 8 0
8 0 0

true
 */